**Direction (1 – 5): **In the given questions, two quantities are given, one as **‘Quantity I’** and another as **‘Quantity II’**. You have to determine relationship between two quantities and choose the appropriate option:

**Q1.** **Quantity I –**Vessel A contains (Q + 36) liter mixture of milk & water in the ratio of 7 : 2, while vessel B contains (2Q + 42) liter mixture of milk & water in the ratio of 2 : 3. If 40% & 46% of mixture from vessel A and B taken out respectively, then remaining mixture in vessel B is 150% of remaining mixture in vessel A. Find the total initial quantity of milk in mixture of vessel A & vessel B together?

**Quantity II – **Two vessels contains mixture of mango juice and orange juice in the ratio of 5 : 3 and 5 : 4 respectively. If 40 liter mixture from first vessel taken out and mixed in second vessel, so new ratio of mango juice and orange juice in second vessel becomes 25 : 19. Find initial quantity of mixture in second vessel?

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Q2.** The ratio between radius of a sphere ball and a cylinder is 6 : 7 and that of between radius & height of cylinder is 7 : 4.

**Quantity I – **Ratio between volume of cylinder and volume of sphere ball.

**Quantity II – **Ratio between surface area of sphere and total surface area of cylinder.

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Q3.** **Quantity I – **Center of semicircle B is O_{1} and radius is 28 cm. find area of shaded figure. BO1 is perpendicular to AC

**Quantity II – **Length of a rectangle is two times of side of square, while ratio between side of square to breadth of rectangle is 8 : 7. If perimeter of rectangle is 28 cm more than perimeter of square, then area of rectangle.

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Q4.** **Quantity I – **Veer invested some amount in scheme A, which offers CI at 20% p.a., and equal amount in scheme B which offers SI at 25% pa. If difference between SI and CI received in 3^{rd} year is Rs. 385, find sum invested in each scheme?

**Quantity II – **Veer, Sameer & Neeraj enter into a business by making investment in the ratio of 9 : 11 :13 respectively. If at the end of one year they got a total profit of Rs. 51150 Rs., then find the profit share of Neeraj?

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Q5.** **Quantity I – **Coaching teacher asked a question to three students A, B & C and probability of question not being answered by three students is 0.5, 0.4, 0.7 respectively. Find the probability that at most two students will solve the question.

**Quantity II – **A bag contains 5 green balls & 7 red balls, if three balls drawn at random from bag, then find probability of getting at least 1 green ball.

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or no relation

**Directions (6-10): Calculate quantity I and Quantity II on the basis of the given information then compare them and answer the following questions accordingly.**

**Q6. Quantity I**: How many days A would require to complete the work, working alone.

If two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3 as efficiently as he actually did, the work would have been completed in 3 days.

**Quantity II**: Arun completes 2/3 of a certain job in 6 days. Lakshya can complete 1/3 of the same job in 8 days and Pulkit can complete 3/4 of the work in 12 days. All of them work together for 4 days and then Arun and Pulkit quit. How long will it take for Lakshya to complete the remaining work alone?

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II

**Q7. Quantity I**: A boat can travel ‘x’ km upstream in 4 hours and ‘y’ km downstream in 3 hours. If the speed of boat in still water is 5 km/h and the boat can travel a distance of ‘x+y’ km downstream in 4 hours, then find the speed of stream?

**Quantity II**: If time taken to cover (D+11) km upstream is thrice the time taken to cover (D–3) km downstream. If ratio of speed of boat in upstream to the downstream is 3 : 7 and time taken to cover (D+18) km downstream is 2.5 hours what will be the speed of current?

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II

**Q8. Quantity I**: The respective ratio between the present ages of son, mother, father and grandfather is 2 : 7 : 8 : 12. The average age of son and mother is 27 yr. What will be mother’s age after 7 yr?

**Quantity II**: The age of the father 5 years ago was 5 times the age of his son. At present the father’s age is 3 times that of his son. What is the present age of the father ?

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II

**Q10.** A boat sails down the river for 10 km and then up the river for 6 km. The speed of the river is 1 km/hr.

**Quantity I:** Speed of boat in still water, if for the whole trip it takes 4 hours.

**Quantity II:** 4 km/hr

(a) Quantity I > Quantity II

(b) Quantity I < Quantity II

(c) Quantity I ≥ Quantity II

(d) Quantity I ≤ Quantity II

(e) Quantity I = Quantity II or No relation

**Solutions**

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