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**Directions (1-5): Read the given information carefully and answer the following questions.**

Total population of Gurgaon sector -29 is 26,000 and there are three sectors i.e. A, B and C in it. Ratio of population of these sectors (A: B: C) is 21: 16: 15. Number of males in sector A is 2500 more than that of females in sector C. Ratio of number of females in sector A to that of males in sector C is 9: 8. Number of females in sector B is 70% of the number of males in sector A.

**Q1. Find the average of number of males in sector A and B is how much more or less than number of females in sector A ?**

(a) 200

(b) 300

(c) 400

(d) 500

(e) 600

**Q2. 68% and 85% of females of sector A and B respectively are working. Then find working females of B is how much percent more or less than that of working females of A.**

**Q3. Total male population of sector A and C together is what percent of total population of these two sectors ?**

**Q4. Find ratio of total number of females in all sectors to that of total number of male population in all sectors?**

(a) 21 : 23

(b) 2 : 3

(c) 41 : 46

(d) 61 : 69

(e) 43 : 46

**Q5. The average of male population of sector B and C is how much more or less than average of female population of these two sectors.**

(a) 40

(b) 50

(c) 60

(d) 70

(e) 80

**Directions (6-10): Study the passage carefully and answer the questions based on it.**

Marks obtained by X in Physics is 160 which is 40% of total marks obtained by him. And marks obtained by Z in chemistry is ¾th of marks obtained by X in Physics. Ratio of total marks obtained by X to Z is 4 : 3. Marks obtained by Y in Maths is equal to marks obtained by Z in Chemistry. And total marks obtained by Y in Physics and Chemistry together is half of total marks obtained by X.

**Q6. If marks obtained by X in Maths is 50% more than marks obtained by him in Chemistry. Then find difference of marks obtained by X in Maths and marks obtained by Y in Maths ?**

(a) 12

(b) 14

(c) 24

(d) 32

(e) 28

**Q7. Marks obtained by Y in Physics and Chemistry together is what percent of total marks obtained by Z ?**

(a) 66 ⅔%

(b) 50%

(c) None of these

(d) 33 ⅓%

(e) 75%

**Q8. What is ratio of marks obtained by Z in Physics and Maths together to marks obtained by X in Chemistry and Physics together ?**

(a) 2 : 5

(b) 1 : 2

(c) cannot be determined

(d) 4 : 3

(e) 2 : 3

**Q9. If Max. marks in each subject is 200. Then find percent of marks obtained by Y ?**

(a) 61 ⅓%

(b) 42 ⅔%

(c) 53 ⅓%

(d) None of these

(e) 47 ⅔%

**Q10. If ratio of marks obtained by Z in Physics and Maths is 2 : 1, then find average marks obtained by X and Z in Physics ?**

(a) None of these

(b) 150

(c) 160

(d) 120

(e) 140

**Directions (11-15): Aakash, Disha and Malik, owner of 3 different shops in Connaught palace, sits and discuss their monthly business. Each of them pay rent of Rs. 1.2 lakhs for their shops. Respective ratio of salaries given by them to workers is in 4 : 5 : 6. Profit for everyone is calculated after deducting their monthly rent and salaries of workers from their total revenue. Highest profit was earned by Disha, i.e. Rs. 520000. Revenue of Malik was 120% of revenue of Aakash. Aakash gave salary of Rs. 48000 to his workers and his profit was 188000 less than profit of Disha.**

**Q11. What is difference between revenue of Disha and profit of Aakash?**

(a) 2.12 lakh

(b) 3.90 lakh

(c) 3.68 lakh

(d) 4.05 lakh

(e) None of these

**Q12. Profit earned by Malik is how much more than salary given by him to his workers?**

(a) 3.36 lakh

(b) 2.96 lakh

(c) 3.56 lakh

(d) 4.12 lakh

(e) None of these

**Q13. Revenue earned by Disha is what % more or less than the Revenue earned by Aakash?**

**Q14. Profit earned by Disha is what % more than the revenue earned by Aakash.**

(a) 0.4%

(b) 4%

(c) 40%

(d) 44%

(e) None of these

**Q15. If the revenue of Aakash increased by 60% and he increased salary of his workers to 1 lakh. Find his new profit if rent remains constant.**

(a) 7 lakhs

(b) 5.8 lakhs

(c) 5.32 lakhs

(d) 4.32 lakhs

(e) 6.32 lakhs

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