SBI PO Mains Quantitative Aptitude Quiz: 17th July


SBI-PO-MAINS-Quantitative-Aptitude-Quiz: 17th July

SBI PO Quantitative Aptitude Quiz

Here, we are providing SBI PO Mains Study plan as there is left not enough time to deal in details. The questions asked in the quantitative aptitude section are calculative and very time-consuming. But once dealt with proper strategy, speed, and accuracy, this section can get you the maximum marks in the examination. Following is the Quantitative Aptitude quiz to help you practice with the best of latest pattern questions.




Directions (1-5): Four traders Satish, Sanjeev, Rawat and Inder sold four types of stationary items i.e., Pen, Pencil, Rubber and Disks. Satish sold 162 Pencils which is 12.5% more than pencils sold by Inder. Average of Pen, Pencil and disks sold by Inder is 162. Pen sold by Sanjeev and Inder is in the ratio 9 : 10 respectively. Rubber sold by Inder is 60% more than rubber sold by Rawat. Pencil sold by Rawat is same as Disks sold by Satish. Rawat sold more pen then rubber. Total number of stationary items sold by Satish is same as pencils sold by all the four traders which is equal to 650. Average number of disk sold by Satish, Sanjeev and inder is 192. Satish sold 192 rubbers which is 28% more than pen sold by Inder or 50% more than pen sold by Satish. Total number of stationary items sold by Sanjeev is 653 and Disks sold by Rawat is 50% more than rubber sold by Sanjeev. Total number of stationary items sold by Inder is 694. 


Q1. Who among the following sold maximum number of stationary items?

Satish
Inder
Sanjeev
Rawat
both (a) and (c)
Solution:



According to table it’s Inder.


Q2. Disks sold by Inder is what percent more than pencil sold by Inder?

66 ⅔%
33 ⅓%
38 ⅓%
50%
57 ⅓%
Solution:



Q3. What is the ratio of Pencil sold by Rawat to disk sold by Sanjeev?

5 : 9
7 : 11
4 : 9
5 : 8
7 : 9
Solution:



Q4. Total number of disks sold by all the four traders is how much more then total number of rubber sold by all the four traders?

99
107
109
117
97
Solution:



Required difference = 765 – 656 = 109

Q5. Rubber sold by Sanjeev is what percent of the disks sold by Satish?

37.5%
50%
62.5%
75%
87.5%
Solution:



Q6. At present, the respective ratio between the ages of A and B is 3 : 4 and that between A and C is 1 : 2. Six years hence, the sum of ages of A, B and C will be 96 years. What is the present age of A ?

12 years
21 years
18 years
15 years
9 years
Solution:

Q7. A jar contains mixture of liquid P and Q in the ratio 4 : 1. If 10ℓ of mixture taken out and same amount of liquid Q poured into jar the ratio becomes 2 : 3 then find how many liters of liquid P contained in jar initially ?

16 L
14 L
12 L
10 L
48 L
Solution:

Q8. A mixture of 240 liters contains milk and water in the respective ratio of 5 : 3. A milkman mixes some more water in it and claim to sell it at cost price. If cost price of pure milk is Rs. 20/liter and water is freely available and milkman made a total profit of 80% on cost price of pure milk then find amount of water he mixed in the milk.

40 liters
30 liters
20 liters
35 liters
45 liters
Solution:

Q9. Average of any 200 consecutive natural numbers is 499.5. If next 1000 numbers more are added in it then find the new average.

1035.5
1299.5
1199.5
1099.5
999.5
Solution:

Q10. A container contains a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5 in the container. How much of the liquid B initially was there in the container? What quantity does the container hold initially?

56 litres, 70 litres
14 litres, 70 litres
65 litres, 72 litres
18 litres, 90 litres
None of these
Solution:

Directions (11-15): In each question two equations numbered (i) and (ii) are given. You have to solve both the equations and give answer

Q11. (i) 4x² + 23x – 215 = 0

(ii) y² + 6y – 55 = 0

If x < y
If x > y
If x ≥ y
If x ≤ y
If x = y or no relation can be established
Solution:

Q12. (i) 8x² + 58x + 39 = 0

(ii) 8y² – 14y – 15 = 0

If x < y
If x > y
If x ≥ y
If x ≤ y
If x = y or no relation can be established
Solution:

Q13. (i) 3x + 7y = 40

(ii) 42x + 21y = 200

If x < y
If x > y
If x ≥ y
If x ≤ y
If x = y or no relation can be established
Solution:

Q14. (i) 5x² + 31x + 48 = 0

(ii) 3y² + 27y + 42 = 0

If x < y
If x > y
If x ≥ y
If x ≤ y
If x = y or no relation can be established
Solution:

Q15. (i) 12x² + 109x + 240 = 0

(ii) 9y² + 99y + 272 = 0

If x < y
If x > y
If x ≥ y
If x ≤ y
If x = y or no relation can be established
Solution:

               






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